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CPL Test Series
Question Bank
Questions for PSR/ PET
Answer the following questions
Test Mode
Training Mode
1. For a distance of 1900 NM between Q and R, a ground speed "out" of 390 kt, a ground speed "back" of 450 kt and an endurance of 8HR (excluding reserves the distance from Q to the point of safe return (PSR) is?
1671 NM.
1655 NM.
1930 NM.
1632 NM.
2. Given: Distance 'A' to 'B' 3623 NM, Groundspeed 'out' 390 kt, Groundspeed 'back' 330 kt. The time from 'A' t the Point of Equal Time (PET) between 'A' and 'B' is?
255 MIN.
288 MIN.
238 MIN.
323 MIN.
3. Given: Distance 'Q' to 'R' 2550 NM, Groundspeed 'out' 550 kt, Groundspeed 'back' 400 kt. Safe endurance 9.5 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'A' is?
2200 NM.
2250 NM.
2267 NM.
2275 NM.
4. Given: Distance 'Q' to 'R' 2160 NM, Groundspeed 'out' 500 kt, Groundspeed 'back' 585 kt, Safe endurance 6 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?
1803 NM.
1618 NM.
1767 NM.
1675 NM.
5. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 40 hours, if the wind component on the outbound leg is 50 knots headwind?
2.1 hours.
1.9 hours.
1.1 hours.
2.3 hours.
6. Two points A and B are 1000 NM apart. TAS =490 kt. On the flight between A and B the equivalent headwind is-20 kt. On the return leg between B and A, the equivalent headwind is +40kt. What distance from A, along the route A to B, is the Point of Equal Time (PET)?
470 NM.
500 NM.
530 NM.
455 NM.
7. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 7 hours, if the wind component on the outbound leg is 65 knots headwind?
4.32 hours.
4.11 hours.
3.91 hours.
4.26 hours.
8. Given: Distance 'Q' to 'R' 1970 NM, Groundspeed 'out' 400 kt, Groundspeed 'back' 485 kt, Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?
1964 NM.
1973 NM.
2013 NM.
2072 NM.
9. For a distance of 1860 NM between Q and R, a ground speed "out" of 385 kt, a ground speed "back" of 465 kt and an endurance of 8 HR (excluding reserves) the distance from Q to the point of safe return (PSR) is?
1865 NM.
1685 NM.
1532 NM.
930 NM.
10. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 20 knots headwind?
4.9 hours.
5.6 hours.
5.3 hours.
5.1 hours.
11. An aircraft was over 'Q' at 1545 hours flying direct to 'R'. Given: Distance 'Q' to 'R' 3016 NM, True airspeed 525 kt, Mean wind component 'out' -90 kt, Mean wind component 'back' +75 kt, Safe endurance 10;00 HR. The distance from 'Q' to the Point os Safe Return (PSR) 'Q' is?
2522 NM.
2570 NM.
2610 NM.
2510 NM.
12. What is the distance from 'Q' to the Point of Safe Return (PSR) for an aircraft that was over 'Q' at 1400 hours flying direct to 'R', given the following data? Distance 'Q' to 'R' 3050 nm, True airspeed 480 kt, Safe endurance 10 Hours, if the mean wind component 'outbound' -90 kt, and the mean wind component 'homebound' is +75 kt.
2290 nm.
1530 nm.
2190 nm.
2375 nm.
13. An aircraft was over 'A' at 1735 hours flying direct to 'B'. Given: Distance 'A' to 'B' 2950 NM, True airspeed 470 kt, Mean wind component 'out' +55 kt, Mean wind component 'back' -75 kt, Safe endurance 9 HR 30 MIN. The distance from 'A' to the Point of Safe Return (PSR) 'A' is?is?
1611 NM.
2141 NM.
1759 NM.
2844 NM.
14. How far can the aeroplane fly out from its base and return in one hour, when flying at TAS 180 kt on a track of 090°, if the W/V is 045°/50kt?
88 nm.
175 nm.
58 nm.
85 nm.
15. Given: Distance 'Q' to 'R' 1960 NM, Groundspeed 'out' 400 kt, Groundspeed 'back' 470 kt, Safe endurance 7 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?
1513 NM.
1542 NM.
1353 NM.
1538 NM.
16. What is the distance to the point of safe endurance if an aircraft has a TAS of 350 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 50 knots headwind?
1605 nm.
1725 nm.
1754 nm.
1713 nm.
17. An aircraft was over 'A' at 1735 hours flying direct to 'B'. Given: Distance 'A' to 'B' 2750 NM, True airspeed 470 kt, Mean wind component 'out' +55 kt, Mean wind component 'back' -75 kt. The ETA for reaching the Point of Equal Time (PET) between 'A' and 'B' is?
1846.
1921.
1944.
1950.
18. An aeroplane is flying at TAS 345 kt on a track of 090°. The W/V is 045°/50kt. How far can the aeroplane fly out from its base and return in one hour?
156 NM.
188 NM.
171 NM.
163 NM.
19. An aircraft is flying at a TAS of 475 knots over a stretch of water between 2 airfield 800 nm apart. What is the distance from the first airfield to the equal time point (ETP) if the wind component is 60 knots head?
398 nm.
451 nm.
350 nm.
480 nm.
20. What is the distance to the point of safe endurance if an aircraft has a TAS of 200 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 85 knots headwind?
505 nm.
865 nm.
819 nm.
854 nm.
21. An aircraft was over 'A' at 1630 hours flying direct to 'B'. Given: Distance 'A' to 'B' 3000 NM, True airspeed 490 kt, Mean wind component 'out +55 kt, Mean wind component 'back' -75 kt. Safe endurance 9 HR 30 MIN.The distance from 'A' to the Point of Safe Return (PSR) 'A' is?
2238 NM.
2259 NM.
2254 NM.
2211 NM.
22. Given: Distance 'A' to 'B' 2100 NM, Groundspeed 'out' 440 kt, Groundspeed 'back' 375 kt. Safe endurance 7 HR 20 MIN. The distance from 'A' to the Point of Safe Return (PSR) 'A' is?
1540 NM.
1447 NM.
1464 NM.
1484 NM.
23. What is the distance to the point of safe endurance if an aircraft has a TAS of 350 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 50 knots headwind?
1714 nm.
1458 nm.
1625 nm.
1554 nm.
24. Given: Distance 'A' to 'B' 1950 NM, Groundspeed 'out' 400 kt, Groundspeed 'back' 385 kt, Safe endurance 7 HR 20 MIN. The distance from 'A' t the Point of Safe Return (PSR) 'A' is?
1464 NM.
1422 NM
1438 NM.
1498 NM.
25. Given: Distance 'Q' to 'R' 2550 NM, Groundspeed 'out' 500 kt, Groundspeed 'back' 450 kt, Safe endurance 9.5 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?
2250 NM.
2201 NM.
2275 NM.
2267 NM.
26. An aeroplane is flying at TAS 250 kt on a track of 090°. The W/V is 045°/50kt. How far can the aeroplane fly out from its base and return in one hour?
145 NM.
136 NM.
116 NM.
123 NM.
27. Two points A and B are 1300 NM apart. TAS = 485 kt. On the flight between A and B the equivalent headwind is -20 kt. On the return leg between B and A, the equivalent headwind is +40 kt. What distance from A. along the route A to B, is the Point of Equal Time (PET)?
655 NM.
647 NM.
690 NM.
676 NM.
28. Given: Distance 'Q' to 'R' 1970 NM, Groundspeed 'out' 475 kt, Groundspeed 'back 485 kt, Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?
1967 NM.
2142 NM.
2160 NM.
2313 NM.
29. Given: Distance 'A' to 'B' 2600 NM, Mean Groundspeed 'out' 380 kt, Mean Groundspeed 'back' 475 kt. Safe endurance 08 HR 30 MIN. The distance from 'A' to the Point of Safe Return (PSR) 'A' is?
1794 NM.
1978 NM
1691 NM.
1730 NM.
30. Given: Distance 'Q' to 'R' 1760 NM, Groundspeed 'out' 435 kt, Groundspeed 'back 385 kt, Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?
1838 NM.
1467 NM.
1313 NM.
1642 NM.
31. An aircraft is flying at a TAS of 300 knots over a stretch of water between 2 airfields 500 nm apart. What is the distance from the first airfield to the equal time point (ETP) if the wind component is 60 knots head?
280 nm.
250 nm.
300 nm.
200 nm.
32. Given: Distance 'Q' to 'R' 1970 NM, Groundspeed 'out' 436 kt, Groundspeed 'back' 485 kt. Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?
2079 NM.
2013 NM.
1964 NM.
2066 NM.
33. Given: Distance 'A' to 'B' 500 NM, Groundspeed 'out' 120 kt, Groundspeed 'back' 130 kt, Safe endurance 6 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?
209 MIN.
220 MIN.
215 MIN.
203 MIN.
34. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 6 hours, if the wind component on the outbound leg is 20 knots headwind?
2.9 hours.
2.6 hours.
3.2 hours.
3.4 hours.
35. How far can the aeroplane fly out from its base and return in one hour, when flying at TAS 280 kt on a track of 090°, if the W/V is 045°/50kt?
188 nm.
175 nm.
158 nm.
135 nm.
36. What is the time to the point of safe endurance if an aircraft has a TAS of 200 knots and safe endurance of 10 hours, if the wind component on the outbound leg is 45 knots headwind?
5.8 hours.
5.9 hours.
6.3 hours.
6.1 hours.
37. Given: Distance 'A' to 'B' 2500 NM, Groundspeed 'out' 370 kt, Groundspeed 'back' 480 kt. Safe endurance 6 HR 30 MIN. The time from 'A' to the Point of Safe Return (PSR) 'A' is?
215 MIN.
230 MIN.
220 MIN.
229 MIN.
38. Given: Distance 'Q' to 'R' 1650 NM, Groundspeed 'out' 450 kt, Groundspeed 'back' 385 kt, Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is ?
1742 NM
1767 NM.
1813 NM.
1867 NM.
39. Given: Distance 'Q' to 'R' 1950 NM, Groundspeed 'out' 455 kt, Groundspeed 'back' 385 kt, Safe endurance 9 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?
1877 NM.
1838 NM.
1713 NM.
1867 NM.
40. How far can the aeroplane fly out from its base and return in one hour, when flying at TAS 350 kt on a track of 090°, if the W/V is 045°/50kt?
180 nm.
157 nm.
173 nm.
158 nm.
41. What is the time to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 4 hours, if the wind component on the outbound leg is 20 knots headwind?
2.9 hours.
2.4 hours.
2.1 hours.
2.6 hours.
42. Given: Distance 'A' to 'B' 2450 NM, Groundspeed 'out' 350 kt, Groundspeed 'back' 385 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?
201 MIN.
220 MIN.
195 MIN.
182 MIN.
43. Given: Distance 'A' to 'B' 2700 NM, Groundspeed 'out' 450 kt, Groundspeed 'back' 500 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?
189 MIN.
165 MIN.
159 MIN.
177 MIN.
44. Given: Distance 'A' to 'B' 2346 NM, Groundspeed 'out' 365 kt, Groundspeed 'back' 480 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?
219 MIN.
197 MIN.
290 MIN.
167 MIN.
45. Given: Distance 'A' to 'B' 2400 NM, Groundspeed 'out' 365 kt, Groundspeed 'back' 480 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B" is?
224 MIN.
197 MIN.
190 MIN.
267 MIN.
46. Given: Distance 'Q' to 'R' 2467 NM, Groundspeed 'out' 500 kt, Groundspeed 'back 400 kt, Safe endurance 9.5 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?
2175 NM.
2167 NM.
2111 NM.
2001 NM.
47. Given: Distance 'A' to 'B' 2600 NM, Groundspeed 'out' 395 kt, Groundspeed 'back' 480 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?
267 MIN.
190 MIN.
217 MIN.
237 MIN.
48. Given: Distance 'Q' to 'R' 2467 NM, Groundspeed 'out' 500 kt, Groundspeed 'back' 450 kt. Safe endurance 9.5 HR. The distance from 'Q' to the Point of Safe Return (PSR) between 'Q' and 'R' is?
2250 NM.
2275 NM.
2267 NM
2221 NM.
49. What is the time to the point of safe return (PSR) if the distance from A to B is 2368 nautical miles, the outbound groundspeed in 365 knots, the homebound groundspeed is 480 knots, and safe endurance is 8 hours 30 minutes?
190 min.
219 min.
209 min.
290 min.
50. An aircraft was over 'A' at 1700 hours flying direct to 'B'. Given: Distance 'A' to 'B' 2900 NM, True airspeed 480 kt, Mean wind component 'out +55 kt, Mean wind component 'back' -75 kt. The ETA for reaching the Point of Equal Time (PET) between 'A' and 'B' is?
1946.
1821.
1934.
1920.
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